TNT wrote:
Dear Scott Smith,
Congratulations! You have guessed correctly in the Lenny Conundrum game (round 206). You have won 306 NP!
Because you were in the first 250 to guess correctly, you also have been awarded a Remnok the Nomad, and receive a trophy and the Lenny Conundrum avatar!
Yours Sincerely,
The Neopets Team!
Web :
http://www.neopets.comDont forget to tell your friends about us - send them a greeting at
http://www.neopets.com/sendgreeting.phtml.
Awesome. This was actually pretty easy:
NOMAD x4 = DAMON
We know N has to be an even number, because DAMON is a multiple of 4. Because a greater number would cause a six-digit result, the only things N can be are 1 and 2, so
N = 2.
From there, we know that 3x4 and 8x4 are the only ways to get a number ending in 2. Since 2x4 is 8,
D = 8.
We also know O must be less than 2, or else it would carry over to the next place, making Nx4=9. Since 2 is already taken, O must be 1 or 0. However, since Dx4 = 32, we know that Ax4+3 = 0. Since Ax4 must be even, Ax4+3 must be odd, so the only possible value for
O = 1.
Back to A. Ax4+3 = something ending in 8, because 8+3 = 11. The only two choices are 2 and 7. However, Mx4 cannot equal M unless it is added to by carrying. That means A would have to be greater than two, so
A = 7.
So far, we have this: 21M78 x4 = 87M12. M is a place value of 100, so we can solve it with linear algebra.
(21078 + 100M) x4 = 87012 + 100M
84312 + 400M = 87012 + 100M
300M = 2700
M = 9
Put it together, and you get
DAMON = 87912.
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